(a/b+c)^2+... (own ?)

[Marius Stănean]

$a,b,c>0 \Longrightarrow$ $\left(\dfrac{a}{b+c}+\dfrac{b}{c+a}+\dfrac{c}{a+b}\right)^2+\dfrac{14abc}{(a+b)(b+c)(c+a)}\ge 4$