(a/b+c)^2+... (own ?)
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- Mesaje: 751
- Membru din: Mar Iul 13, 2010 7:15 am
- Localitate: Zalau
(a/b+c)^2+... (own ?)
$a,b,c>0 \Longrightarrow$ $\left(\dfrac{a}{b+c}+\dfrac{b}{c+a}+\dfrac{c}{a+b}\right)^2+\dfrac{14abc}{(a+b)(b+c)(c+a)}\ge 4$
Quae nocent docent