Inegalitate cu 2 variabile
Scris: Vin Apr 28, 2017 10:24 am
Demonstrati ca $\frac{(a+b)^2}{2}+\frac{a+b}{4} \geq \ a\sqrt{b}+b\sqrt{a}$, oricare ar fi numerele reale pozitive $a$ si $b$.
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